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March 29, 2017

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Assuming that a typical popular music CD comprises 12 songs each of 8500 KB, what would the effective transmission speed need to be capped at in order to extend the download time to 2 hours? Express your final answer in bits per second, using scientific notation correct to two decimal places

  • Math - ,

    12 songs * 8500 *10^3 Bytes/song = 1.02*10^8 Bytes = 8.16*10^8 bits

    Transmission speed
    = 8.16*10^8 bits/7200 s
    = 1.13*10^5 bits/s

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