Posted by Lucinda on Thursday, May 27, 2010 at 5:40am.
hey i found the working to this somewhere else and it was
its a buffer so
pH=pKa + log[base]/[acid]
=9.241 + log [70.9x.1300]/[11.1x0.278]
= 9.72
which makes sense but...
i also had that question on my assignment and got it wrong
the actual answer is 9.54
i cannot find a reason for this but as we were told not to use that eqn in chem then there must be another way to do it
calculate the percent composition for NaOH and the tell how many grams of each elements are in a 14 gram sample.
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