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Mathematics
Trigonometry
Trigonometric Identities

Prove tanAsin2A=2sin^2a

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asked by Sarah
13 years ago
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2. 0

LS

= (tanA)(sin2A)
= sinA/cosA(2sinAcosA)
= 2sin^2 A
= RS

answered by Reiny
13 years ago
1. 0
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