Posted by Nonno on Wednesday, May 26, 2010 at 7:40pm.
nice problem!
remember that the sum of any two sides of a triangle has to be greater than the third side, so let's try the possible 3 numbers that have a sum of 8.
6 1 1 - no
5 1 2 - no
5 2 1 - no
4 1 3 - no
4 2 2 - no
4 3 1 - no
3 1 4 - no
3 2 3 - yes
any others would simply be permutations of the above.
Using Heron's formula --- http://www.mathopenref.com/heronsformula.html
area = √(4(1)(1)(2))
= 2√2
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