Posted by **Jim B** on Wednesday, May 26, 2010 at 6:56pm.

I don't understand can someone help me on how to figure this out please !!

Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour an train B is traveling at 100 miles per hour. Train A passes a station at 2:25 pm. If train B passes the same station at 2:37 pm,. at what time will train B catch up to train A?

- Algebra -
**lynnette**, Wednesday, May 26, 2010 at 7:36pm
why did train b which is traveling faster then train a, need to catch up to train a? doesn't make sense.did train b stop somewhere along the way, or did train be have a different starting point?

- Algebra -
**Jim B**, Wednesday, May 26, 2010 at 7:45pm
That's the question asked on the homework.

- Algebra -
**lynnette**, Wednesday, May 26, 2010 at 7:52pm
not enough facts present or the there's a misprint.

a formula useful for similar equations, though, is distance = rate x time

- Algebra -
**Jennifer**, Thursday, October 4, 2012 at 8:11pm
Let the station be at x = 0. After 2:37 pm, train A is at

x(A) = (2:37-2:25)/(60 minutes per hour)*80 mph + 80 * t,

or

x(A) = (12 min / 60 min per hour) * 80 mph + 80 * t

x(A) = 16 + 80 * t

where t is hours after 2:37

for train B,

x(B) = 100*t

Set x(A) = x(B) or

100*t = 16 + 80*t

20*t = 16

t = 3/4 hour

Add this time to 2:37 to find the time when they catch up with each other

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