If 36 g of potassium chloride are dissolved in 100mL of water at 40 C to form a saturated solution, how many grams of potassium chloride would be required to form a saturated solution in 250 mL of water at the same temperature?
250mL/100mL=1.5
36g * 2.5=90g
90 grams KCl (potassium chloride) will be needed to make a saturated solution in 250 mL of water at 40 degrees C.
That's really easy.
you do 250/100 which is 2.5
then, you multiply that to the mass of KCl and get 90g like what the other person said.
To determine the amount of potassium chloride required to form a saturated solution in 250 mL of water at the same temperature, we can use a proportion.
First, we need to find the concentration of the saturated solution in terms of grams per milliliter.
Given that 36 g of potassium chloride is dissolved in 100 mL of water, we can calculate the concentration as follows:
Concentration = mass of solute / volume of solvent
Concentration = 36 g / 100 mL
Concentration = 0.36 g/mL
Now, we can set up a proportion to find the amount of potassium chloride needed for 250 mL of water:
(0.36 g/mL) / (36 g) = (x g) / (250 mL)
Cross-multiplying, we get:
0.36 g * 250 mL = 36 g * x
90 g mL = 36 g x
Dividing both sides by 36 g gives:
90 g mL / 36 g = x
2.5 mL = x
Therefore, you would need 2.5 grams of potassium chloride to form a saturated solution in 250 mL of water at the same temperature.