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September 18, 2014

September 18, 2014

Posted by **Fred** on Wednesday, May 26, 2010 at 5:41pm.

I know how to use complement to get the answer. Why does P(Not face)* P(Not face) produce a different and wrong answer?

- Math-Probability -
**PsyDAG**, Thursday, May 27, 2010 at 12:10pmIf

*both*have to be face cards, then the probability of losing will include either the probability of*one*or*both*not being a face card.

P(face) * P(not face) + P(not face) * P(not face) = ?

- Math-Probability -
**Fred**, Thursday, May 27, 2010 at 2:54pmThank you. Now I know what I forgot. There are two ways of P(face)*P(not face) then add P(not face)* P(not face)

Went brain dead.

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