Wednesday

July 30, 2014

July 30, 2014

Posted by **Fred** on Wednesday, May 26, 2010 at 5:41pm.

I know how to use complement to get the answer. Why does P(Not face)* P(Not face) produce a different and wrong answer?

- Math-Probability -
**PsyDAG**, Thursday, May 27, 2010 at 12:10pmIf

*both*have to be face cards, then the probability of losing will include either the probability of*one*or*both*not being a face card.

P(face) * P(not face) + P(not face) * P(not face) = ?

- Math-Probability -
**Fred**, Thursday, May 27, 2010 at 2:54pmThank you. Now I know what I forgot. There are two ways of P(face)*P(not face) then add P(not face)* P(not face)

Went brain dead.

**Related Questions**

math - Two cards are chosen from a standard deck of 52 playing cards without ...

MATH Prob. - You are dealt two cards successively without replacement from a ...

Statistics - A standard deck of 52 playing cards is composed of 4 suits. Each ...

Math - I can not seem to figure out this question. Can someone please help? Two ...

general - From a standard deck of 52 cards, all of the clubs and the jack of ...

statistics - Anne, Joe and Lynn, in this order, will take turns to draw two ...

Stats - Directions: Suppose you have a standard deck 52 cards (4 suits: hearts...

math - Three cards are drawn without replacement from a well-shuffled standard ...

AP Statistics - A standard deck of cards consisting of 52 cards, 13 in each of 4...

finite math - three cards are randomly drawn without replacement from a standard...