Posted by **Fred** on Wednesday, May 26, 2010 at 5:41pm.

The question is to draw two cards from a standard deck without replacement. To win, both cards must be face cards. What is the probability you will LOSE?

I know how to use complement to get the answer. Why does P(Not face)* P(Not face) produce a different and wrong answer?

- Math-Probability -
**PsyDAG**, Thursday, May 27, 2010 at 12:10pm
If *both* have to be face cards, then the probability of losing will include either the probability of *one* or *both* not being a face card.

P(face) * P(not face) + P(not face) * P(not face) = ?

- Math-Probability -
**Fred**, Thursday, May 27, 2010 at 2:54pm
Thank you. Now I know what I forgot. There are two ways of P(face)*P(not face) then add P(not face)* P(not face)

Went brain dead.

## Answer this Question

## Related Questions

- Math (Probability) - A standard deck of cards contains 52 cards. Of these cards ...
- math - Two cards are chosen from a standard deck of 52 playing cards without ...
- MATH Prob. - You are dealt two cards successively without replacement from a ...
- Statistics - A standard deck of 52 playing cards is composed of 4 suits. Each ...
- Math - I can not seem to figure out this question. Can someone please help? Two ...
- general - From a standard deck of 52 cards, all of the clubs and the jack of ...
- statistics - Anne, Joe and Lynn, in this order, will take turns to draw two ...
- Stats - Directions: Suppose you have a standard deck 52 cards (4 suits: hearts...
- Math - A standard deck of playing cards is shuffled and three people each choose...
- math - Three cards are drawn without replacement from a well-shuffled standard ...

More Related Questions