Posted by Anonymous on Wednesday, May 26, 2010 at 5:06pm.
How do you solve this ;
5^(3y) = 8^ (y1)
I think the first step is (3y)log 5 = (y1)log 5
2nd step:3ylog5 = ylog51log5
3rd step: 3ylog5  ylog5 = 1log5
4th step: y(2ylog5  log5) = 1log5
From here I don't know, normal if I got rid of the 2y I would divide 1log 5 by log5log5 ...

Algebra II Help  Anonymous, Wednesday, May 26, 2010 at 6:41pm
Solved it
Answer This Question
Related Questions
 Algebra  will you please show me step by step in solving: 1/2 log b + 3 log c. ...
 Algebra help  f(x)=x^34x^2x+4 How do I find the xintercept for this? This is...
 Algebra 2  how do i solve these two problems? 3log(base5)^(x^2+9)6 = 0 log(...
 ALGEBRA HELP  When solving the equation, what property was used to go from step...
 Precalculus  This is for solving exponential/logarithmic functions: (This is a ...
 Quick math help  In which step below does a mistake first appear in simplifying...
 pre algebra  solve the equation step by step.list each step along with the ...
 Algebra  Please show me step by step on solving this problem? log₅(2x9...
 Algebra 1StepbyStep  Can someone show me how to solve these stepbystep? ...
 Algebra 2  Can you please explain step by step on how to do this problem? ...
More Related Questions