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April 18, 2014

April 18, 2014

Posted by **shasha** on Tuesday, May 25, 2010 at 8:36pm.

the amount of snowfall falling in a certain mountain range is normally distributed with a mean of 86 inches, and a standard deviation of 12 inches. what is the probability that the mean annual snowfall during 36 randomly picked years will exceeds 88.8 inches?

- stats. plz help i have exams in two days! -
**christopher**, Tuesday, May 25, 2010 at 8:52pm0.0808

- stats. plz help i have exams in two days! -
**shasha**, Tuesday, May 25, 2010 at 9:07pmhow did u come up with it?thanks

- stats. plz help i have exams in two days! -
**PsyDAG**, Wednesday, May 26, 2010 at 11:29amZ = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1)

Since only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to that Z score.

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