The length of a rectangle is 7 cm more than its width. The area of the rectangle is 120 sq. cm. What is the width of the rectangle?

Can you solve ...

x(x+7) = 120 as a quadratic?

Please check

x=8

yes,

8(15) = 120

To find the width of the rectangle, we need to set up an equation using the given information. Let's say the width of the rectangle is represented by 'x' cm.

According to the given information, the length of the rectangle is 7 cm more than its width. So, the length would be represented by 'x + 7' cm.

The formula for the area of a rectangle is length multiplied by width. In this case, the area of the rectangle is given as 120 sq. cm. So, we can set up the equation:

(x + 7) * x = 120

To solve this equation, we can simplify it:

x^2 + 7x = 120

Now, let's rearrange the equation to bring all the terms to one side:

x^2 + 7x - 120 = 0

To solve this quadratic equation, we can factor it or use the quadratic formula. In this case, let's factor the equation:

(x + 15)(x - 8) = 0

This gives us two possible values for the width of the rectangle: x + 15 = 0 or x - 8 = 0.

Solving these equations gives us two possible values for x: x = -15 or x = 8.

Since width cannot be negative, we can conclude that the width of the rectangle is 8 cm.