Posted by JohnJ on Tuesday, May 25, 2010 at 1:30pm.
3y^2+8=0
(3y+2)+(3y2)=8+0
3y=8
y=3/8
Radical and Rational Exponent
this chapter is hard for me.

college algebra  bobpursley, Tuesday, May 25, 2010 at 4:13pm
No, it is wrong.
3y^2=8
y^2=8/3
Now you can't to anymore in the real number system, as there is no such thing as a square root of a negative number. But if you define i as sqrt (1), then
y=+ sqrt (8/3) * i