Posted by **JohnJ** on Tuesday, May 25, 2010 at 1:30pm.

3y^2+8=0

(3y+2)+(3y-2)=8+0

3y=-8

y=3/8

Radical and Rational Exponent

this chapter is hard for me.

- college algebra -
**bobpursley**, Tuesday, May 25, 2010 at 4:13pm
No, it is wrong.

3y^2=-8

y^2=-8/3

Now you can't to anymore in the real number system, as there is no such thing as a square root of a negative number. But if you define i as sqrt (-1), then

y=+- sqrt (8/3) * i

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