Posted by JohnJ on Tuesday, May 25, 2010 at 1:30pm.
No, it is wrong.
3y^2=-8
y^2=-8/3
Now you can't to anymore in the real number system, as there is no such thing as a square root of a negative number. But if you define i as sqrt (-1), then
y=+- sqrt (8/3) * i
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