Use logarithms to solve log 8 / log x < 1.
I understand that there are 2 cases: when x is negative or positive.
I don't understand how it affects the answer though.
pre-cal - bobpursley, Monday, May 24, 2010 at 10:55pm
log8<logx if logx is positive
Log8>logx if logx is negative.
10^8>x if x is less one