a sled is pulled at a velocity across a horizontal snow surface. if a force of 8.0x10 to the first power N is being applied to a sled rope at an angle of 53 degrees to the ground, what is the magnitude force of friction
To calculate the magnitude of the force of friction, we need to determine the components of the applied force that are parallel and perpendicular to the snow surface.
First, let's determine the perpendicular component of the applied force, which acts against the force of gravity. We can calculate it using the formula:
F_perpendicular = F_applied * cos(theta)
where F_applied is the applied force and theta is the angle at which the force is applied.
F_perpendicular = (8.0 * 10^1 N) * cos(53 degrees)
F_perpendicular = 8.0 * 10^1 N * 0.6 (rounded to one decimal place)
F_perpendicular = 48 N
Next, let's calculate the parallel component of the applied force, which is responsible for overcoming the force of friction. We can calculate it using the formula:
F_parallel = F_applied * sin(theta)
F_parallel = (8.0 * 10^1 N) * sin(53 degrees)
F_parallel = 8.0 * 10^1 N * 0.8 (rounded to one decimal place)
F_parallel = 64 N
Assuming the sled is moving with a constant velocity, the force of friction will be equal in magnitude but opposite in direction to the parallel component of the applied force. Therefore, the magnitude of the force of friction is 64 N.