How many grams of Ni(OH)2 are produced from the reaction of 30.0 mL of 1.75 M NaOH solution?
You have to specify a complete reaction.
NaOH+ ????> Ni(OH)2 + ????
To determine the number of grams of Ni(OH)2 produced, we need to use stoichiometry and the given information.
First, let's write the balanced chemical equation for the reaction between NaOH and Ni(OH)2:
2 NaOH + NiCl2 -> 2 NaCl + Ni(OH)2
From the balanced equation, we can see that 2 moles of NaOH react to produce 1 mole of Ni(OH)2.
Given:
Volume of NaOH solution (V) = 30.0 mL = 0.0300 L
Molarity of NaOH solution (M) = 1.75 M
To find the moles of NaOH, we use the formula:
moles of NaOH = volume (in liters) × molarity
moles of NaOH = 0.0300 L × 1.75 M
moles of NaOH = 0.0525 moles
Since the stoichiometric ratio is 2 moles of NaOH to 1 mole of Ni(OH)2, we can calculate the moles of Ni(OH)2 produced:
moles of Ni(OH)2 = 0.0525 moles ÷ 2
moles of Ni(OH)2 = 0.02625 moles
Now, we need to find the molar mass of Ni(OH)2. The atomic mass of Ni is 58.6934 g/mol, and the atomic masses of H and O are 1.00784 g/mol and 15.999 g/mol, respectively.
Molar mass of Ni(OH)2 = (58.6934 g/mol × 1) + (1.00784 g/mol × 2) + (15.999 g/mol × 2)
Molar mass of Ni(OH)2 = 58.6934 g/mol + 2.01568 g/mol + 31.998 g/mol
Molar mass of Ni(OH)2 = 92.70708 g/mol
Finally, we can find the mass of Ni(OH)2 produced:
mass of Ni(OH)2 = moles of Ni(OH)2 × molar mass of Ni(OH)2
mass of Ni(OH)2 = 0.02625 moles × 92.70708 g/mol
mass of Ni(OH)2 = 2.4306 grams
Therefore, approximately 2.43 grams of Ni(OH)2 are produced from the reaction of 30.0 mL of 1.75 M NaOH solution.