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December 22, 2014

December 22, 2014

Posted by **Thomas** on Sunday, May 23, 2010 at 11:13pm.

- CALCULUS -
**Joe**, Monday, May 24, 2010 at 12:12amThis is actually a question from co-ordinate geometry. If (x1,y1), (x2,y2) and (x3,y3) are the vertices of a triangle then its area = (1/2))(x1(y2-y3)+x2(y3-y1)+x3(y1-y2))

The co-ordinates of the vertices aren't very clear in your Q but assuming that the three points are (-2.1,3),(7.8,-4)& (5,0.2) the area of the triangle is 10.99 sq. units

Ajit

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