Posted by **Don** on Sunday, May 23, 2010 at 11:09pm.

Use the discriminant to determine how many real number solutions the equation has.

t^2 + 8t + 16 = 0

- Algebra -
**Anonymous**, Sunday, May 23, 2010 at 11:13pm
discriminant= b2-4ac

(8)^2-4(1)(16)

64-64=0

One real root (because it equals 0).

If it was a positive number, there would be two real roots. If it was a negative number, there would be two COMPLEX roots.

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