Posted by kaitlyn on Sunday, May 23, 2010 at 11:04pm.
For a can with both ends closed, Area reqd. = 2”Ērh + 2”Ēr^2 where r=6,h=4 and assume ”Ē=22/7, A=2640/7 sq in.
If one end of the can is open then A=2”Ērh + ”Ēr^2 = 264 sq in.
Area of circle = πr^2
Multiply by 2 to get top and bottom.
Circumference = 2πr
Area of side = 4 *2πr
Combine the data.
376.8 in.2
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