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November 26, 2014

November 26, 2014

Posted by **kaitlyn** on Sunday, May 23, 2010 at 11:04pm.

- Math -
**Joe**, Monday, May 24, 2010 at 12:36amFor a can with both ends closed, Area reqd. = 2”Ērh + 2”Ēr^2 where r=6,h=4 and assume ”Ē=22/7, A=2640/7 sq in.

If one end of the can is open then A=2”Ērh + ”Ēr^2 = 264 sq in.

- Math -
**PsyDAG**, Monday, May 24, 2010 at 10:42amArea of circle = πr^2

Multiply by 2 to get top and bottom.

Circumference = 2πr

Area of side = 4 *2πr

Combine the data.

- Math -
**candy**, Tuesday, July 12, 2011 at 2:30pm376.8 in.2

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