An aluminum cylindrical juice can has a height of 4 in. and a radius of 6 in. How many square inches of aluminum are needed to make the can?
Math - Joe, Monday, May 24, 2010 at 12:36am
For a can with both ends closed, Area reqd. = 2¡Çrh + 2¡Çr^2 where r=6,h=4 and assume ¡Ç=22/7, A=2640/7 sq in.
If one end of the can is open then A=2¡Çrh + ¡Çr^2 = 264 sq in.
Math - PsyDAG, Monday, May 24, 2010 at 10:42am
Area of circle = πr^2
Multiply by 2 to get top and bottom.
Circumference = 2πr
Area of side = 4 *2πr
Combine the data.
Math - candy, Tuesday, July 12, 2011 at 2:30pm