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January 25, 2015

January 25, 2015

Posted by **anonymous** on Sunday, May 23, 2010 at 5:56pm.

sin[arccos(-2/7)] ?

- precal -
**Damon**, Sunday, May 23, 2010 at 6:38pmcos is - in quadrants 2 and 3

adjacent is -2, hypotenuse is 7, what is opposite?

7^2 - 2^2 = 49 - 4 = 45 = 9 * 5

sqrt(9*5) = 3 sqrt (5)

so sin = +/- 3 sqrt(5) /7

- precal -
**anonymous**, Sunday, May 23, 2010 at 6:59pmThank you!

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