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March 6, 2015

March 6, 2015

Posted by **sh** on Friday, May 21, 2010 at 1:26pm.

To find the zeros, I combined the equations cosx-sinx=0

What's next?

- Calculus -
**Damon**, Friday, May 21, 2010 at 4:57pmWatch out.

Between 0 and 45 degrees, the cos is bigger than the sin.

Between 45 and 90, the sin is bigger than the cos.

In both sectors, there is area between them. The same in fact.

Therefore for quadrant 1, do 0 to pi/4 and double the result.

Then look at the other three quadrants.

- Calculus -
**Damon**, Friday, May 21, 2010 at 5:05pmintegral cos x dx from 0 to pi/4 = sin pi/4 - sin 0

= sqrt(2)/2

integral sin x dx from 0 to pi/4 = -cos pi/4 + 0 = -sqrt(2) /2

difference = sqrt 2

then integral from 0 to pi/2 = 2 sqrt 2

etc

- Calculus -
**Damon**, Friday, May 21, 2010 at 5:07pmOh, forgot you do not know where sin = cos

sure cos x - sin x = 0

1 -tan x = 0

tan x = 1

x = pi/4 (x = y at 45 deg)

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