What about it? Are we solving for x ??
if so, then ....
4 cosx + 5 = 6/cosx
4cos^2x + 5cosx = 6
4cos^2x + 5cosx - 6 = 0
(4cosx - 3)(cosx + 2) = 0
cosx = 3/4 or cosx = -2 , Not possible since |cosx| ≤1
so cosx = 3/4
x = 41.4° or x = 221.4°
HELPPPPPPP (TRIG) - 4cos(x) 5=6sec(x)
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