Posted by Kate on Thursday, May 20, 2010 at 8:35pm.
Math (trig) - Reiny, Thursday, May 20, 2010 at 10:47pm
What about it? Are we solving for x ??
if so, then ....
4 cosx + 5 = 6/cosx
4cos^2x + 5cosx = 6
4cos^2x + 5cosx - 6 = 0
(4cosx - 3)(cosx + 2) = 0
cosx = 3/4 or cosx = -2 , Not possible since |cosx| ≤1
so cosx = 3/4
x = 41.4° or x = 221.4°
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