The concentration of NaOH is normally in the range of 3-6 M when they peel potatoes and soak them in a solution of NaOH , remove them and spray them off. If I have 45.7 mL of 0.500M of H2SO4 required to react completely with a 20.0 mL sample of NaOh. What is the molar concentration of the NaOH solution?

Is the answer 2.28 M NaOH? If not please assist
Thank you

look good to me.

thank you

To find the molar concentration of the NaOH solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between NaOH and H2SO4.

The balanced equation for the reaction between NaOH and H2SO4 is:
2NaOH + H2SO4 -> Na2SO4 + 2H2O

According to the equation, 2 moles of NaOH reacts with 1 mole of H2SO4. Therefore, the moles of NaOH can be calculated using the molarity and volume of H2SO4:

moles of H2SO4 = molarity of H2SO4 * volume of H2SO4
= 0.500 M * 45.7 mL
= 22.85 mmol (millimoles) of H2SO4

Since the ratio of NaOH to H2SO4 is 2:1, the moles of NaOH will be half of the moles of H2SO4:

moles of NaOH = 22.85 mmol / 2
= 11.425 mmol of NaOH

Now, we can calculate the molarity of NaOH using the moles of NaOH and the volume of NaOH solution:

molarity of NaOH = moles of NaOH / volume of NaOH solution (in L)
= 11.425 mmol / 20.0 mL (convert to L by dividing by 1000)
= 0.5725 M

Therefore, the molar concentration of the NaOH solution is 0.5725 M, which is different from the answer you provided. Hence, the correct answer is not 2.28 M NaOH.

Please let me know if I can help you with anything else.