Posted by **gill** on Thursday, May 20, 2010 at 6:27am.

A baby bounces up and down in her crib. Her mass is 13.5 kg, and the crib mattress can be modeled as a light spring with force constant 682 N/m.

If she were to use the mattress as a trampoline—losing contact with it for part of each cycle—what minimum amplitude of oscillation does she require?

- PHYSICS -
**Damon**, Thursday, May 20, 2010 at 6:41am
w = 2 pi f = sqrt(k/m)

x = A sin wt

v = A w cos wt

a = -A w^2 sin wt

max a = A w^2 = g

so

g = A w^2

A = g m/k

- PHYSICS -
**Anonymous**, Friday, May 21, 2010 at 4:39am
to damon. that doesnt help. be more detailed.

- PHYSICS -
**ANON**, Sunday, November 8, 2015 at 1:24pm
Damon is Stating that-

F=1/T T=2*pi/w so T= 2pi/sqrt(k/m)

using our values T=2pi/sqrt(682/13.50)=.884004

Therefore F=1/.884004 -->=1.13121

For the second part acceleration=Aw^2 which must equal the acc. of gravity(g)

g=Aw^2 w=sqrt(k/m) so w=7.107638

plugging into our equation the equation g=Aw^2: 9.8=A*(7.107638^2)

9.8=50.518518*A

9.8/50.518518=A, so A=.193988 meters

which is about 19.39 cm

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