Posted by andrea on Wednesday, May 19, 2010 at 10:56pm.
heat lost by alloy + heat gained by water = 0
[mass alloy x specific heat alloy x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
Related Questions
chemistry - When 45 grams of an alloy is dropped into 100.0 grams of water at 25...
Chemistry - I have a few problems im having trouble with, any help..? 1. If a ...
Chemistry - Imagine that your water heater has broken, but you want to take a ...
chemistry - An insulated beaker contains 250.0 grams of water at 25C. Exactly 41...
Chemistry - A 30.5 g sample of an alloy at 94.0°C is placed into 48.7 g ...
Chemistry - A 30.5 g sample of an alloy at 93.7°C is placed into 50.1 g ...
Chemistry - A 30.5 g sample of an alloy at 94.0°C is placed into 48.7 g ...
Chemistry - HELP!!! An unknown metal having a mass of 14.00g is dropped into 11....
Chemistry - A 34.6 g block of metal at 2.1oC is dropped into 100.0 g of water at...
Chemistry - A piece of copper metal is initially at 100 C. It is dropped into a ...
For Further Reading