How much heat will be released if 30 g of octane is burned in excess of oxygen?
C8 H18 + 12.5 O2 yields 8CO2 + 9H2O Delta H= -5483.4 kJ
To determine the heat released when 30 g of octane (C8 H18) is burned in excess oxygen, you need to use the given balanced equation and the molar mass of octane.
1. Calculate the number of moles of octane:
Molar mass of octane (C8 H18) = (12.01 g/mol x 8) + (1.01 g/mol x 18)
= 114.23 g/mol
Number of moles of octane = 30 g / 114.23 g/mol
2. Use the stoichiometry of the balanced equation to determine the heat released per mole of octane:
From the balanced equation, the coefficient of octane (C8 H18) is 1.
Therefore, the heat released per mole of octane is -5483.4 kJ.
3. Calculate the heat released when 30 g of octane is burned:
Heat released = (-5483.4 kJ/mol) x (moles of octane)
Substitute the number of moles of octane from step 1 into the equation to calculate the heat released.
To calculate the amount of heat released when 30 g of octane is burned, we need to use the given balanced chemical equation and the molar mass of octane.
Step 1: Convert the mass of octane to moles
Molar mass of octane (C8H18) = 114.22 g/mol
Number of moles of octane = mass of octane / molar mass of octane
= 30 g / 114.22 g/mol
Step 2: Calculate the heat released per mole of octane
From the balanced equation, we know that the molar ratio of octane to heat released is 1:5483.4 kJ.
Therefore, the heat released per mole of octane is -5483.4 kJ/mol.
Step 3: Calculate the total heat released
Total heat released = heat released per mole of octane x number of moles of octane
= (-5483.4 kJ/mol) x (number of moles of octane)
By plugging in the values from Step 1 and Step 2, we can calculate the total heat released.