Posted by **FKO** on Wednesday, May 19, 2010 at 5:07pm.

A group of 45 tokens is arranged into three piles such that each pile contains a different prime number of tokens. What is the greatest number of tokens possible in any of the three piles?

Thanks

- Math 6th grade -
**tchrwill**, Wednesday, May 19, 2010 at 6:05pm
37 + 3 + 5 = 45

- Math 6th grade -
**Abigail**, Thursday, May 20, 2010 at 11:06am
45 divided by three is 15!

- Math 6th grade -
**tchrwill**, Thursday, May 20, 2010 at 6:36pm
A group of 45 tokens is arranged into three piles such that EACH PILE CONTAINS A DIFFERENT PRIME NUMBER OF TOKENS.

What is the greatest number of tokens possible in any of the three piles?

37 RESULTING IN 37 + 3 + 5 = 45.

- Math 6th grade -
**Clauddd**, Wednesday, June 2, 2010 at 5:07pm
45

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