Posted by FKO on .
A group of 45 tokens is arranged into three piles such that each pile contains a different prime number of tokens. What is the greatest number of tokens possible in any of the three piles?
Thanks

Math 6th grade 
tchrwill,
37 + 3 + 5 = 45

Math 6th grade 
Abigail,
45 divided by three is 15!

Math 6th grade 
tchrwill,
A group of 45 tokens is arranged into three piles such that EACH PILE CONTAINS A DIFFERENT PRIME NUMBER OF TOKENS.
What is the greatest number of tokens possible in any of the three piles?
37 RESULTING IN 37 + 3 + 5 = 45. 
Math 6th grade 
Clauddd,
45