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July 23, 2014

July 23, 2014

Posted by **Bill** on Wednesday, May 19, 2010 at 12:35pm.

- algebra -
**drwls**, Wednesday, May 19, 2010 at 2:34pmCall the small pizza radius r and the large pizza radius R.

R = 2r +3

pi R^2 = pi r^2 -33

= pi*(4r^2 + 6r + 9)

3r^2 + 6r + (33/pi) +9 = 0

Solve that quadratic for r.

Are you sure the problem did not say

"The area of the small pizza is 33 pi square inches less than the large pizza. " ?

The answer would be easier to write down in that case, because the pi factors would cancel out

- algebra -
**Anonymous**, Saturday, June 1, 2013 at 5:01pmhk,hh

- algebra -
**Anonymous**, Saturday, June 1, 2013 at 5:01pmhk,hh

- algebra -
**Anonymous**, Saturday, June 1, 2013 at 5:04pmhk,hh

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