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August 1, 2014

August 1, 2014

Posted by **joe** on Wednesday, May 19, 2010 at 11:24am.

- physical science -
**drwls**, Wednesday, May 19, 2010 at 11:35amThe deceleration rate will be

a = F/m = 2 m/s^2. The time to stop is given by

t = Vo/a = (10 m/s)/(2m/s^2) = 5 s

- physical science -
**joe**, Saturday, July 20, 2013 at 12:08amcalculate the KE of a 1500 kg. car travelling at 60 km/h

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