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physical science

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What will the stopping distance be for a 1,000-kg car if -2,000 N of force are applied when the car is traveling 10 m/s?

  • physical science - ,

    The deceleration rate will be
    a = F/m = 2 m/s^2. The time to stop is given by
    t = Vo/a = (10 m/s)/(2m/s^2) = 5 s

  • physical science - ,

    calculate the KE of a 1500 kg. car travelling at 60 km/h

  • physical science - ,

    45000j

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