Posted by Anonymous on .
The molar heat of vaporization of ethanol is 43.5 kJ/mo. Calculate the heat required to vaporize 25.0 g of ethanol at its boiling point.
Ethanol is (2C 5H OH)
Could someone please write the equation? (is the equation q=CmT)
I wonder if that is kJ/month or kJ/mol. I assume kJ/mol. No, the equation isn't q = CmT. It's mass x delta Hvap.