Posted by Katie on Tuesday, May 18, 2010 at 9:58pm.
Several layers of derivatives here ...
remember for y = e^u
dy/dx = e^u (du/dx)
so f'(x) = e^(xsin2x)(d(xsin2x)/dx)
= e^(xsin2x)(x(2cos2x) + sin2x) using the product rule for the last part
Thank you! :)
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