Friday

October 9, 2015
Posted by **Katie** on Tuesday, May 18, 2010 at 9:58pm.

F(x)=e^(xsin2x)

This isn't homework, it's review for our exam. Couldn't remember how to work it :( Thanks!

- Calculus -
**Reiny**, Tuesday, May 18, 2010 at 10:53pmSeveral layers of derivatives here ...

remember for y = e^u

dy/dx = e^u (du/dx)

so f'(x) = e^(xsin2x)(d(xsin2x)/dx)

= e^(xsin2x)(x(2cos2x) + sin2x) using the product rule for the last part

- Calculus -
**Katie**, Wednesday, May 19, 2010 at 4:29pmThank you! :)