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November 29, 2014

November 29, 2014

Posted by **buggy** on Tuesday, May 18, 2010 at 7:31pm.

- Geometry -
**Reiny**, Tuesday, May 18, 2010 at 9:15pmlet the radius be r

then the area of one of the sectors would simply be 1/4 of the area of the circle,

which would be (1/4)πr^2 or πr^2/4

- Geometry -
**buggy**, Tuesday, May 18, 2010 at 9:24pmif the sides are each 6 of the square then how would you find the segment?

- Geometry -
**Reiny**, Tuesday, May 18, 2010 at 9:38pmThe 6 is the hypotenuse of a right-angled triangle with the other sides as the radius

r^2 + r^2 = 36

r^2 = 18

r = √18

sector = (1/4)π(√18)^2 = 9π/2

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