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posted by Keith on Tuesday, May 18, 2010 at 3:17pm.

x^2+y=9, x-y+3=0. Need to solve using substitution method.

from the second ... y = x+3 sub into first x^2 +x+3 = 9 x^2 + x - 6 = 0 (x+3)(x-2) = 0 x = -3 or x = 2 sub both values into y = x+3 to find their corresponding y's

Thanks

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