posted by john on .
A 125-newton box rests on a plank 3.00 meters long, one end of which is 1.00 meters higher than the other end. Find the components of the force the box exerts
Parallel to the inclined plane=
Perpendicular to the inclined plane=
The plank is inclined
A = sin^-1 1/3 = 19.5 degrees.
Weight force parallel to plane:
125 N*sin A = 41.7 N
Perpendicular to plane:
125 N*cosA = 117.9 N