Posted by **ablin** on Tuesday, May 18, 2010 at 9:22am.

a force of 3.5 N is applied to a spring which obeys Hooke's law and produces and extension of 0.07m.

calculate the spring constant

what is the size of the force that will produce and extension of 4.0 cm

caluclate the unstretched length of the spring if its total length is 17.5 cm when applied force is 5 N.

- physic -
**drwls**, Tuesday, May 18, 2010 at 11:16am
The spring constant k = Force/extension.

In your case, k = 3.5/0.07 = 50 N/m

Use that k to calculate the force when the extension = 0.04 m. It should be (4/7) times 3.5 = ___ Newtons.

For the final question, calculate the extension when F = 5N,

extension = F/k = 0.1 m = 10 cm

and subtract that from 0.175 m to get the unstretched length.

## Answer this Question

## Related Questions

- physics - Sir Robert Hooke (1635-1703), studied the elastic properties of ...
- physics - Mere and Ruth investigated the relationship between the applied force...
- Physics - Mere and Ruth investigated the relationship between the applied force...
- Physics - The spring on a popgun obeys Hooke's law and requires a force of 220 N...
- Physics - The spring on a popgun obeys Hooke's law and requires a force of 220 N...
- Physics - The spring on a popgun obeys Hooke's law and requires a force of 220 N...
- physic - Hooke's law describes a certain light spring of unstretched length 30.0...
- Physics - I think that for energy of a spring I should use (1/2)(k)(x^2) and (1/...
- Physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...
- Physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...