Posted by emily on Tuesday, May 18, 2010 at 6:56am.
Is that really cos(2x) or do you mean cos^2 x?
I will assume that you really do mean cos(2x). In that case
cos(2x) = cos^2 x - sin^2 x
= 2 cos^2 x -1
y = 6 cos^2x -3 + 5 = 6 cos^2 x - 2
cos^2 x = (y+2)/6
cos x = sqrt[(y+2)/6)]
You can use that to solve for x, if that is what the question is all about.
You cannot solve a single equation for both x and y.
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