a 90.0 kg person stands 1.00 m from a 60.0 kg person sitting on a bench nearby. what is the magnitude of the gravitalional force between them?

F = G M1 M2 / d^2

where G = 6.67 * 10^-11 N m^2/kg^2

Prof. Holt wrote a physics text.

To calculate the magnitude of the gravitational force between two objects, we can use Newton's law of universal gravitation, which states that the force between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them.

The formula for the gravitational force (F) is given by:

F = G * (m1 * m2) / r^2

Where:
F is the gravitational force
G is the gravitational constant (approximately 6.674 × 10^-11 N*m^2/kg^2)
m1 and m2 are the masses of the two objects
r is the distance between their centers of mass

In this case, m1 is the mass of the standing person (90.0 kg), m2 is the mass of the person sitting on the bench (60.0 kg), and r is the distance between them (1.00 m).

Let's substitute these values into the formula to calculate the magnitude of the gravitational force:

F = (6.674 × 10^-11 N*m^2/kg^2) * (90.0 kg * 60.0 kg) / (1.00 m)^2

F = (6.674 × 10^-11 N*m^2/kg^2) * (5400 kg^2) / (1.00 m^2)

F = (6.674 × 10^-11 N*m^2/kg^2) * 5400

F ≈ 0.00036012 N

Therefore, the magnitude of the gravitational force between the two people is approximately 0.00036012 Newtons.

Who is holt? Does he or she teach a special kind of physics?