Monday

July 28, 2014

July 28, 2014

Posted by **Sara!** on Monday, May 17, 2010 at 8:49pm.

three computers are randomly selected and tested. what is the probability that all 3 are defective if the first and second ones are not replaced after being tested.

a. 1/760

b.1/1140

c.27/8000

d.3/5000

i chose D, is this correct

- math -
**Damon**, Monday, May 17, 2010 at 9:00pmFirst one 3/20

Second one 2/19

third one 1/18

3/20*2/19*1/18 = 1/(3*20*19) =1/1140

- math -
**Hope**, Monday, December 6, 2010 at 5:37pmThe answer is B Explanation: 3/20*2/19*1/18=1/(3*20*19)=1/1140

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