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October 20, 2014

October 20, 2014

Posted by **Lyndsie** on Monday, May 17, 2010 at 7:13pm.

- Algebra II -
**Reiny**, Monday, May 17, 2010 at 8:04pmlet the plane's position be P

so in triangle ABP, angle A = 30° ( a bearing of 120 = 90+30)

let's find angle P

sinP/250 = sin 30/200

(case 1)

angle P = 38.682

then angle A = 113.328°

BP/sin113.328 = 200/sin30

BP = 372.63 km

case 2

angle P = 141.318

then angle A = 8.682°

BP/sin8.682 = 200/sin30

BP = 60.38 km

both answers make sense, since the triangle results in the "ambiguous case"

- Algebra II -
**Ashleyh**, Monday, May 14, 2012 at 10:31am1. A passenger in an airplane at an altitude of 10 km sees two towns to the east of the plane. The angle of depression to town A is 28o and the angle of depression to town B is 55o. How far apart are the two towns?

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