posted by Sarah on .
1) Write a balanced chemical equation for the reaction between Cu(NO3)2 * 3 H2O and NaOH. Underline the formula for the precipitate produced by this reaction. (The water of hydration in Cu(NO3)2 * 3 H2O appears as liquid water on the right side of the equation)
2) Calculate the molar masses of copper(II) nitrate trihydrate and of the precipitate formed by this reaction.
3)Calculate the number of moles of NaOh in 5.00 mL of a 1.00 M solution of NaOH.
*Please help with all questions!*
1. Cu(NO3)2.3H2O(aq) + NaOH(aq) --> Cu(OH)2(s) + H2O + NaNO3(aq)
We can't underline but (s) means a solid ppt. You will need to balance it.
2. This is a stoichiometry problem. You have worked many like it.
3. moles = M x L.