Calculate the number of C atoms, H atoms, and O atoms, in 1.50 grams of glucose (C6H1206).
moles glucose = 1.5/molar mass glucose = ??.
Then 1 mole glucose contains 6.022 x 10^23 molecules. Therefore, ?? moles will contain xx molecules glucose.
Then each molecules contains 6 C, 6 O, and 12 H atoms.
If the molar mass and the moles of glucose is .000833. What do I do next? I don't have a scientific calculator with me now.
To calculate the number of C atoms, H atoms, and O atoms in 1.50 grams of glucose (C6H12O6), we need to use the concept of moles and Avogadro's number.
Step 1: Calculate the molar mass of glucose (C6H12O6)
To calculate the molar mass of glucose, we need to sum up the atomic masses of all the elements present. The atomic masses are as follows:
Carbon (C) = 12.01 g/mol
Hydrogen (H) = 1.01 g/mol
Oxygen (O) = 16.00 g/mol
Molar mass of glucose (C6H12O6):
6(C) + 12(H) + 6(O) = 6(12.01) + 12(1.01) + 6(16.00) = 72.06 g/mol
Step 2: Calculate the number of moles of glucose
To calculate the number of moles of glucose, we divide the given mass (1.50 grams) by the molar mass of glucose (72.06 g/mol):
Number of moles = Given mass / Molar mass
Number of moles = 1.50 g / 72.06 g/mol
Step 3: Calculate the number of each type of atom
Since the ratio of C atoms, H atoms, and O atoms in glucose is 6:12:6, we can use this ratio to calculate the number of each type of atom.
Number of C atoms = Number of moles of glucose × Avogadro's number × 6
Number of H atoms = Number of moles of glucose × Avogadro's number × 12
Number of O atoms = Number of moles of glucose × Avogadro's number × 6
Avogadro's number is approximately 6.022 × 10^23 (atoms/mol).
Substitute the value of the number of moles into the formulas above to calculate the number of each type of atom.
I'll calculate it for you:
Number of moles = 1.50 g / 72.06 g/mol ≈ 0.0208 mol
Number of C atoms = 0.0208 mol × 6.022 × 10^23 atoms/mol × 6 = 7.52 × 10^22 atoms
Number of H atoms = 0.0208 mol × 6.022 × 10^23 atoms/mol × 12 = 1.50 × 10^23 atoms
Number of O atoms = 0.0208 mol × 6.022 × 10^23 atoms/mol × 6 = 7.52 × 10^22 atoms
Therefore, 1.50 grams of glucose contains approximately 7.52 × 10^22 carbon atoms, 1.50 × 10^23 hydrogen atoms, and 7.52 × 10^22 oxygen atoms.