Posted by **Carmen** on Sunday, May 16, 2010 at 11:58pm.

Determine the number of real-number solutions to the equation

-2x2 - x - 5 = 0, given the graph of y = -2x2 - x - 5

- Algebra -
**Jen**, Monday, May 17, 2010 at 12:33pm
You have to use the discriminant to find the real number solutions. discriminant=b^2-4ac

a=-2, b=-1, c=-5 (the co-efficients from your equation, in order)

1-4(-2)(-5)=1-40=-39

Since it came out to -39, there are no real number solutions (because it is negative). When the answer is positive, there are two real number solutions. When the answer is zero, there is one real number solution.

## Answer this Question

## Related Questions

- College Algebra - Consider only the discriminant, b2 - 4ac, to determine whether...
- Math - Can someone please check my work for me? Write an equation of the line ...
- MATH 157 - How do I determine the real number solution for the following problem...
- Algebra - Solve. (–10x3 + 30x – 20) ÷ (–5x + 5) • 2x2 – 2x + 4 • –2x2 – 2x – 4...
- math - How many real number solutions exist for 2x2 8x 8 = 0?
- College Math - For questions 1-2, apply the quadratic formula to find the roots...
- Algebra - If the sides perpendicular to the wall have length x feet, which of ...
- AlgebraB-2 - 1. What are the coordinates of the vertex of the graph? Is it a ...
- math - State the solutions, or estimated solutions, to each quadratic equation ...
- Algebra2 - Complete parts a – c for each quadratic function. a. Find the y-...