Posted by Carmen on Sunday, May 16, 2010 at 11:58pm.
Determine the number of realnumber solutions to the equation
2x2  x  5 = 0, given the graph of y = 2x2  x  5

Algebra  Jen, Monday, May 17, 2010 at 12:33pm
You have to use the discriminant to find the real number solutions. discriminant=b^24ac
a=2, b=1, c=5 (the coefficients from your equation, in order)
14(2)(5)=140=39
Since it came out to 39, there are no real number solutions (because it is negative). When the answer is positive, there are two real number solutions. When the answer is zero, there is one real number solution.
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