What is the resistance of a 40 watt light bulb if it is it to full brilliance by a current of .33amps?
R = Power/I^2 = 40/(0.33)^2 = ___ ohms
That is the resistance at the operating temperature, with 120 V applied. The resistance will be less as the bulb filament heats up. You could verify that with an ohmeter
To determine the resistance of a 40-watt light bulb when operated at full brilliance with a current of 0.33 amps, we need to use Ohm's Law, which states that the resistance (R) of a component is equal to the voltage (V) across it divided by the current (I) flowing through it.
Ohm's Law formula:
R = V / I
Given:
Power (P) = 40 watts
Current (I) = 0.33 amps
Finding the voltage:
The power (P) of an electrical device can be calculated by multiplying the voltage (V) across it by the current (I) flowing through it.
Power formula:
P = V * I
Rearranging the formula to solve for voltage (V):
V = P / I
Calculating the voltage:
V = 40 watts / 0.33 amps
Once we determine the voltage, we can use Ohm's Law to find the resistance.
R = V / I
Now, to calculate:
Step 1: Calculate the voltage:
V = 40 watts / 0.33 amps
Step 2: Use Ohm's Law to find the resistance:
R = V / I
By following these steps, you will be able to determine the resistance of the 40-watt light bulb when operated at full brilliance with a current of 0.33 amps.