Sunday

February 1, 2015

February 1, 2015

Posted by **Ted** on Sunday, May 16, 2010 at 8:45pm.

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**Ms. Sue**, Sunday, May 16, 2010 at 8:57pmWhat are your choices?

- math -
**Reiny**, Sunday, May 16, 2010 at 10:10pmWhat did you not like about my answer yesterday?

http://www.jiskha.com/display.cgi?id=1273956086

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**Ted**, Sunday, May 16, 2010 at 10:45pmthanks.

my choices are:

A. v=4b^4h^2 divided by 3

B. v=2b^4h^2 divided by 6

C. v=4b^2h divided by3

D. v=2b^2h divided by 3

E. v=4b^4h^2 divided by 6.

this is for ms.sue.

- math -
**Reiny**, Sunday, May 16, 2010 at 11:01pmTed, neither in todays nor in yesterdays post did you give any dimensions.

Your choices of answers suggest that the base had side b and the height was h

so matching my answer of (4/3)x base area x height

would be C. 4b^2h/3 or (4/3) b^2 h

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