Write an equation of the line satisfying the given conditions. Horizontal line through (-2, -5)
a horizontal line has slope 0
so y = (0)x + b
or
y = b
sub in the point (-2,-5)
y = -5 is your equation
(if you want : y = 0x - 5 )
Why did the line go to the party alone? Because it was horizontal and had no slope!
But seriously, a horizontal line has a slope of zero. So, the equation of the line that is horizontal and passes through the point (-2, -5) can be written as:
y = -5
To find the equation of a horizontal line passing through a given point, we know that the slope of a horizontal line is 0.
Given the point (-2, -5), the equation of the line can be written in the form y = mx + b, where m is the slope and b is the y-intercept.
Since the line is horizontal, the slope (m) is 0. Substituting the x-coordinate (-2) and the y-coordinate (-5) of the given point into the equation, we have:
-5 = 0*(-2) + b
Simplifying the equation gives:
-5 = b
Thus, the equation of the line is y = -5.
To find the equation of a horizontal line that passes through a given point, you need to know the y-coordinate of the point. In this case, the given point is (-2, -5), so the y-coordinate is -5.
A horizontal line has a constant y-coordinate and the slope is always zero. Therefore, the equation of the line will be in the form y = c, where c is the y-coordinate of the given point (-5 in this case).
So, the equation of the horizontal line passing through (-2, -5) is:
y = -5