Posted by **Rick** on Saturday, May 15, 2010 at 8:42pm.

I am having a lot of difficulty trying to figure out how to put two math (word problems) questions into an expression. Can someone help me, I can do the rest from there. An explanation on the math formula would be great too.

here's the two questions.

1. The projected number of men and women enrolled in US colleges, in millions, is modeled in the following formulas: Women: N=0.007x+4.1 Men: N=0.01x +3.9

What is the project enrollment of women in 2004, and what is the projected enrollment of men in 2004?

2. The water level of a reservoir is measured over a 5-month period of time. At the beginning, the level is 25ft. During this time, the level fell 3 ft., then rose 2ft., the rose 1 foot, then fell 4ft., and then rose 2ft. What is the reservoir’s level at the end of the 5-month period?

- algebra -
**Reiny**, Saturday, May 15, 2010 at 9:32pm
1. Unless we know the definition of x, .... ?

If x is the time in years, just plug in the values of 2004 into both equations.

2. What is 25 - 3 + 2 + 1 - 4 + 2

- algebra -
**Rick**, Saturday, May 15, 2010 at 10:30pm
The projected number of men and women enrolled in US colleges, in millions, is modeled in the following formulas: Women: N=0.007x+4.1 Men: N=0.01x +3.9

N represents enrollment, in millions, x years after 1984 (I left this part out last posting).

What is the project enrollment of women in 2004, and what is the projected enrollment of men in 2004?

With x equaling years after 1984, should I subtract 1984 from 2004 to get 20 years then multiply this by 0.007 for the women? What is the +4.1? Do I multiply 4.1 times 20 years also? I’m not sure how to put this into an equation. My guess:

N=20*.007+20*4.1=222

- algebra -
**Reiny**, Saturday, May 15, 2010 at 10:38pm
yes, for 2004, x = 20

but you substituted incorrectly

the 4.1 in a constant in millions and it was the enrollment in 1984

The 4.1 has no variable with it to substitute, (that's why it is called a constant)

(note that for 1984, x = 0, and

N = .007(0) + 4.1 = 4.1

for 2004, the women's enrollment is

N = .007(20) + 4.1 = 4.24

so there are 4,240,000 women enrolled

Do the same for the Men equation.

## Answer This Question

## Related Questions

- Algebra - I am having such a hard time in this class. Hopefully someone here can...
- Parabolas in standard form! - Hello, I am having the worst time trying to solve ...
- algebra - i have got a lot of math problems to do...if you can just help me with...
- Algebra - Hi! Today I was absent from my algebra class, and they learned how to ...
- Algebra 1 - I'm having a hard time understanding distance rate and time word ...
- Physics - I am having some problems trying to figure this out. Series circuits I...
- Algebra Packet (a lot of questions!) - Ok, there a lot of questions from the ...
- history - To me everyone is the same and by having someone under someone else it...
- Math - I missied school Friday and am not sure how to do my math homework. here ...
- Basic Algebra - I am having a hard time trying to figure out this problem, if ...

More Related Questions