Saturday

October 25, 2014

October 25, 2014

Posted by **Rick** on Saturday, May 15, 2010 at 8:42pm.

here's the two questions.

1. The projected number of men and women enrolled in US colleges, in millions, is modeled in the following formulas: Women: N=0.007x+4.1 Men: N=0.01x +3.9

What is the project enrollment of women in 2004, and what is the projected enrollment of men in 2004?

2. The water level of a reservoir is measured over a 5-month period of time. At the beginning, the level is 25ft. During this time, the level fell 3 ft., then rose 2ft., the rose 1 foot, then fell 4ft., and then rose 2ft. What is the reservoir’s level at the end of the 5-month period?

- algebra -
**Reiny**, Saturday, May 15, 2010 at 9:32pm1. Unless we know the definition of x, .... ?

If x is the time in years, just plug in the values of 2004 into both equations.

2. What is 25 - 3 + 2 + 1 - 4 + 2

- algebra -
**Rick**, Saturday, May 15, 2010 at 10:30pmThe projected number of men and women enrolled in US colleges, in millions, is modeled in the following formulas: Women: N=0.007x+4.1 Men: N=0.01x +3.9

N represents enrollment, in millions, x years after 1984 (I left this part out last posting).

What is the project enrollment of women in 2004, and what is the projected enrollment of men in 2004?

With x equaling years after 1984, should I subtract 1984 from 2004 to get 20 years then multiply this by 0.007 for the women? What is the +4.1? Do I multiply 4.1 times 20 years also? I’m not sure how to put this into an equation. My guess:

N=20*.007+20*4.1=222

- algebra -
**Reiny**, Saturday, May 15, 2010 at 10:38pmyes, for 2004, x = 20

but you substituted incorrectly

the 4.1 in a constant in millions and it was the enrollment in 1984

The 4.1 has no variable with it to substitute, (that's why it is called a constant)

(note that for 1984, x = 0, and

N = .007(0) + 4.1 = 4.1

for 2004, the women's enrollment is

N = .007(20) + 4.1 = 4.24

so there are 4,240,000 women enrolled

Do the same for the Men equation.

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