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March 26, 2017

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A 5.1 kg bowling ball and a 7.1 kg bowling ball rest on a rack 1.07 m apart.

(a) What is the force of gravity exerted on each of the balls by the other ball?

(b) At what separation is the force of gravity between the balls equal to 2.0 10-9 N?

  • Physics - ,

    part b says 2.0 E-9

  • Physics - ,

    F = G M1 M2 / d^2
    = 6.67 * 10^-11 * 5.1 * 7.1 / 1.07^2

  • Physics - ,

    part b
    2*10^-9 = 6.67*10^-11*5.1*7.1/d^2
    solve for d

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