Homework Help: Physics

Posted by Kelly17 on Friday, May 14, 2010 at 7:11pm.

A 5.1 kg bowling ball and a 7.1 kg bowling ball rest on a rack 1.07 m apart.

(a) What is the force of gravity exerted on each of the balls by the other ball?

(b) At what separation is the force of gravity between the balls equal to 2.0 10-9 N?

Physics - Kelly17, Friday, May 14, 2010 at 7:18pm
part b says 2.0 E-9
Physics - Damon, Friday, May 14, 2010 at 8:33pm
F = G M1 M2 / d^2
= 6.67 * 10^-11 * 5.1 * 7.1 / 1.07^2
Physics - Damon, Friday, May 14, 2010 at 8:34pm
part b
2*10^-9 = 6.67*10^-11*5.1*7.1/d^2
solve for d

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