Posted by Adam on Friday, May 14, 2010 at 2:47pm.
Tarzan stands on a branch, petrified with fear as a leopard approaches. Fortunately, Jane is on a branch of the same height in a nearby tree, holding a 25m long vine of negligible mass attached directly above the point midway between her and Tarzan. Jane grasps the vine and steps off her branch with negligible initial velocity. How soon does she reach Tarzan? Find an expression for the maximum tension in the vine in terms of Jane’s weight mg and the maximum angle the vine makes with the vertical.

college physics  find any other answers let me know!!!, Saturday, November 27, 2010 at 12:44am
how soon does she reach tarzan
1/2T=1/2*2*pi*sqrt(L/g)
=pi*sqrt(25m/9.8m/s)=5.0s
the rest i'm still working on

college physics  Anonymous, Sunday, November 28, 2010 at 5:32pm
would the equation to sovle for the maximum tension be:
T=mg + Fc = mg + m*v^2/R ?????
does anyone have the expression for the maximum angle?
Answer This Question
Related Questions
 College Physics  Tarzan swings on a vine from a cliff to rescue Jane, who is ...
 physics  Tarzan, King of the Jungle (mass = 73.2 kg), grabs a vine of length 14...
 physics  Two children hang by their hands from the same tree branch. The branch...
 physics  Two children hang by their hands from the same tree branch. The branch...
 physics  Two children hang by their hands from the same tree branch. The branch...
 physics  Two children hang by their hands from the same tree branch. The branch...
 physics  Two children hang by their hands from the same tree branch. The branch...
 Physics  Two children hang by their hands from the same tree branch. The branch...
 physics  Save Two children hang by their hands from the same tree branch. The ...
 physics (clear answer)  Two children hang by their hands from the same tree ...
More Related Questions