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April 24, 2014

April 24, 2014

Posted by **Zach** on Thursday, May 13, 2010 at 10:58pm.

- Math -
**Reiny**, Friday, May 14, 2010 at 9:13amA good idea is to take 6 identical coins and line them up as above (6 quarters)

draw a line from the centre of the bottom middle circle to the centre of the left circle of the middle row.

Draw a horizontal line from the centre of the left circle in the second row to the point of tangency with the other circle in that row.

Draw a vertical from that point of tangency to the centre of the bottom middle circle.

You should have a right-angled triangle with hypotenuse 1, short leg as 0.5 and vertical leg as x

x^2 + .5^2 = 1^2

x^2 = .73 or 3/4

x = √3/2

so the distance from the outside of the bottom middle circle to the centre of the 6 circles is

√3/2 + .5

Then the height of the whole stack is

2(√3/2 + .5)

= √3 + 1

- AP Statistics -
**Anonymous**, Sunday, May 16, 2010 at 10:14amIn a particular game, a fair die is tossed. If the number of spots showing is either four or five, you win $1. If the number of spots showing is six, you win $4. And if the number of spots showing is one, two, or three, you win nothing. You are going to play game twice.

The probability that you win $4 both times is

a)1/6

b)1/3

c)1/36

d)1/4

e)1/12

- Math -
**jill**, Saturday, March 5, 2011 at 5:06pm1/3

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