Homework Help: calculus I integral

Posted by John on Thursday, May 13, 2010 at 5:03pm.

Is this correct?
Evaluate 2x∫1 3t(t^2 + 1)^2 dt

u= t^2 + 1
du= 2t dt 1/2du=tdt
2x∫1 3u^2 1/2du
3/2 2x∫1 1/3u^3 + c
3/2 [1/3 u^3]
3/2(1/3(2x)^3) - 3/2(1/3(1)^3)
Answer= 4x - 1/2

No one has answered this question yet.

Answer this Question

Related Questions

Calculus AP - Evaluate the integral interval from [0 to pi] t sin(3t)dt Use ...
calc: arc length - find the exact length of this curve: y = ( x^3/6 ) + ( 1/2x...
Calculus - If x = t^2 + 1 and y = t^3, then d^2y/dx^2 = I know I can solve for t...
calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...
calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...
Calculus - How do I evaluate 2x∫1 3t(t^2 + 1)^2 dt?
Calculus AP - hi again im really need help TextBook: James Stewart:Essential ...
Calculus - so we are doing integrals and I have this question on my assignment ...
Calculus - Evaluate the integral: the integral of [5e^(2t)]/[1+4e^(2t)]dt. I ...
Calculus - Evaluate the integral: the integral of [5e^(2t)]/[1+4e^(2t)]dt. I ...

For Further Reading

First Name:
School Subject:
Answer: