Posted by khin on Thursday, May 13, 2010 at 6:13am.
ClCH2COOH ==> ClCH2COO^- + H^+
Ka = (H^+)(ClCH2COO^-)/((ClCH2COOH)
(H^+)=x
(ClCH2COO^-)=x
(ClCH2COOH) = 0.02-x
a. 0.010
The answer is C).015
Find x through the quadratic equation x^2^ +(1.4E-3)x - (2.8E-5)=0
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