Posted by **andy** on Thursday, May 13, 2010 at 2:08am.

The solubility product constant (Ksp) for the dissolution of PbSO4 as represented by the chemical equation is 1.7x10-8.

PbSO4 (s)= Pb2+ (aq) + SO42- (aq)

Calculate the mass (g) of PbSO4 that dissolves in 1100 mL of water.

- chemistry -
**DrBob222**, Thursday, May 13, 2010 at 11:12am
Pb^+2 = x

SO4^-2 = x

Substitute into Ksp and solve.

Then convert M into g/1100 mL.

- chemistry -
**Confused**, Saturday, October 16, 2010 at 3:50am
What about this question?

Calculate the mass (g) of PbSO4 that will dissolve in 2000 mL of 0.0694 M K2SO4 solution. The equation represents the solubility process.

PbSO4 (s) Pb2+ (aq) + SO42- (aq)

Ksp = 1.7 x 10-8

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