Posted by **andy** on Thursday, May 13, 2010 at 2:08am.

The solubility product constant (Ksp) for the dissolution of PbSO4 as represented by the chemical equation is 1.7x10-8.

PbSO4 (s)= Pb2+ (aq) + SO42- (aq)

Calculate the mass (g) of PbSO4 that dissolves in 1100 mL of water.

- chemistry -
**DrBob222**, Thursday, May 13, 2010 at 11:12am
Pb^+2 = x

SO4^-2 = x

Substitute into Ksp and solve.

Then convert M into g/1100 mL.

- chemistry -
**Confused**, Saturday, October 16, 2010 at 3:50am
What about this question?

Calculate the mass (g) of PbSO4 that will dissolve in 2000 mL of 0.0694 M K2SO4 solution. The equation represents the solubility process.

PbSO4 (s) Pb2+ (aq) + SO42- (aq)

Ksp = 1.7 x 10-8

## Answer this Question

## Related Questions

- chemistry - What about this question? Calculate the mass (g) of PbSO4 that will ...
- medicinal chemistry - the solubility product of PbSO4 at 298K is 1.6x10^-8 mol^...
- medicinal chemistry - the solubility product of PbSO4 at 298K is 1.6x10^-8 mol^...
- chem - if 12 L of a saturated solution of PbSO4 is found to contain 0.46g of ...
- AP CHEMISTRY - A voltaic cell is constructed that is based on the following ...
- chemistry - To a 100.0 mL solution containing 0.0100 M Ba(NO3)2 and 0.0100 M Pb(...
- Chemistry! URGENT! - Calculate the solubility, in molL―1, of lead sulfate...
- chemistry - The solubility product constant (Ksp) for the dissolution of Cu(OH)2...
- chemistry - Solid Na2SO4 is added to a solution which is 0.014 M in Pb(NO3)2 and...
- Chemistry - what is the molar solubility of lead sulfate in 1.0 X 10^-3 M Na2SO4...

More Related Questions